Fn = -4100 + 8000 + 1200 = 5100 N., Due
East. = Net force.
a = Fn/m = 5100/6800 = 0.75 m/s^2, Due
East.
a boat has a mass of 6800 kg. its engine generate a drive force of 4100 N, due west, while the wind exerts a force of 8000 N, due east, and the water exerts a resistive force of 1200 N due east. what is the magnitude and direction of the boats accelerations? (answer 0.309 m/s^2) I need a step by step help please
2 answers
Find net force: -4100N + 800N + 1200N= -2100N
F=ma
-2100N = 6800kg x a
/6800 kg /6800kg
-2100N/6800kg = a
a = -0.31
F=ma
-2100N = 6800kg x a
/6800 kg /6800kg
-2100N/6800kg = a
a = -0.31
1 answer