V = sqrt(x^2+y^2).
X = 1.3 m/s, Y = 2.4 m/s, V = ?.
A boat crosses a river of width 164 m in which
the current has a uniform speed of 1.3 m/s.
The pilot maintains a bearing (i.e., the direction
in which the boat points) perpendicular
to the river and a throttle setting to give a
constant speed of 2.4 m/s relative to the water.
What is the magnitude of the speed of the
boat relative to a stationary shore observer?
2 answers
v=_/(1.3^2 + 2.4^2)
v = 2.72
v = 2.72