A BMX rider is coming up to a ramp that is set to 27.0° and the end point is 4.20 m above the ground. They travel up the ramp at a steady speed of 7.80 m/s. What speed will they have just before they hit the ground?

Answer 1

Vo = 7.8m/s[27o].
Xo = 7.8*Cos27 = 6.95 m/s.
Yo = 7.8*sin27 = 3.54 m/s.

Y^2 = Yo^2 + 2g*h = 3.54^2 + 19.6*4.2 = 95,
Y = 9.7 m/s.

V = sqrt(Xo^2+Y^2) = sqrt(6.95^2 + 9.7^2) =