Before the collision, the blue ball is moving with a speed of 3 m/s in a certain direction while the green ball is moving with a speed of 2 m/s in the opposite direction. After the collision, the blue ball comes to rest and remains at the same location while the green ball continues its motion in its original direction. To find the speed of the green ball after the collision, we can use the principle of conservation of momentum. Since momentum is conserved in an isolated system, the momentum before the collision is equal to the momentum after the collision. Therefore, the mass of the blue ball multiplied by its initial velocity is equal to the mass of the green ball multiplied by its final velocity. Let's denote the final velocity of the green ball as Vg.
(0.15 kg * 3 m/s) + (0.15 kg * (-2 m/s)) = 0.15 kg * Vg
0.45 kg m/s - 0.3 kg m/s = 0.15 kg * Vg
0.15 kg * Vg = 0.15 kg m/s
Vg = 1 m/s
Hence, the speed of the green ball after the collision is 1 m/s in its original direction.
A blue and a green billiard ball, each with a mass of 0.15 kg, collide directly. Before the collision, the blue ball had a speed of 3 m/s while the green ball had a speed of 2 m/s. After the collision, the blue ball stays in place while the green ball continues in motion. In 3-4 sentences, represent the situation before and after the collision and calculate the speed of the green ball after the collision. Be sure to discuss direction.
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