Let's go through each question step-by-step.
Question 1: Direction of travel of the balls
- The blue ball is traveling at 3 m/s (positive direction), while the green ball is traveling at -2 m/s (negative direction). Since they have opposite speeds with one being negative, they are moving towards each other before the collision.
- Correct response: In opposite directions, towards each other.
Question 2: Momentum of the balls before the collision
- Momentum is calculated as \( p = m \cdot v \).
- For the blue ball: \( p_{blue} = 0.15 \text{ kg} \cdot 3 \text{ m/s} = 0.45 \text{ kg.m/s} \).
- For the green ball: \( p_{green} = 0.15 \text{ kg} \cdot (-2 \text{ m/s}) = -0.3 \text{ kg.m/s} \).
- Correct response: 0.45 kg.m/s ; -0.3 kg.m/s.
Question 3: Total momentum of the blue ball after the collision
- Since the blue ball stays in place after the collision, its speed is 0 m/s.
- Thus, the momentum of the blue ball after the collision is \( p_{blue} = 0.15 \text{ kg} \cdot 0 \text{ m/s} = 0 \text{ kg.m/s} \).
- Correct response: 0 kg.m/s.
Question 4: Momentum and direction of the green ball after the collision
- Since the blue ball is stationary and the system conserves momentum, the total momentum before the collision (0.45 kg.m/s - 0.3 kg.m/s = 0.15 kg.m/s) must equal the total momentum after the collision.
- The green ball takes on the momentum of the system, and we already determined that its direction of travel would be the same as its original direction (which was negative).
- Given that the blue ball is stationary (0 kg.m/s), the green ball must have momentum of 0.3 kg.m/s but in the opposite direction as we previously established from conservation of momentum.
- Correct response: 1.0 kg.m/s in the same direction from its original travel direction.
Overall, the responses are:
- In opposite directions, towards each other.
- 0.45 kg.m/s ; -0.3 kg.m/s.
- 0 kg.m/s.
- 1.0 kg.m/s in the same direction from its original travel direction.