A blood pressure measurement consists of two numbers: the systolic pressure, which is the maximum pressure taken when the heart is contracting, and the diastolic pressure, which is the minimum pressure taken at the beginning of the heartbeat. Blood pressures were measured, in millimeters of mercury (mmHg), for a sample of 10 adults.

Systolic Diastolic Systolic Diastolic
133 91 105 66
112 75 157 103
107 71 154 94
110 74 134 87
108 69 115 83
Compute the least-squares regression line for predicting the diastolic pressure from the systolic pressure. Round the slope and y-intercept to at least four decimal places.

11 answers

To compute the least-squares regression line for predicting diastolic pressure (\(y\)) from systolic pressure (\(x\)), we will use the following formulas:

  1. Slope (\(b\)): \[ b = \frac{n(\sum xy) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2} \]

  2. Y-intercept (\(a\)): \[ a = \frac{\sum y - b(\sum x)}{n} \]

Where:

  • \(n\) is the number of data points.
  • \(\sum x\) is the sum of the systolic pressures.
  • \(\sum y\) is the sum of the diastolic pressures.
  • \(\sum xy\) is the sum of the product of systolic and diastolic pressures.
  • \(\sum x^2\) is the sum of the squares of the systolic pressures.

Step 1: Gather the Data

First, we will extract our data into convenient variables:

| Systolic (\(x\)) | Diastolic (\(y\)) | |------------------|-------------------| | 133 | 91 | | 112 | 75 | | 107 | 71 | | 110 | 74 | | 108 | 69 | | 105 | 66 | | 157 | 103 | | 154 | 94 | | 134 | 87 | | 115 | 83 |

Step 2: Calculate the Necessary Sums

Let's calculate the required summations:

  • \(n = 10\)
  • \(\sum x = 133 + 112 + 107 + 110 + 108 + 105 + 157 + 154 + 134 + 115 = 1285\)
  • \(\sum y = 91 + 75 + 71 + 74 + 69 + 66 + 103 + 94 + 87 + 83 = 823\)
  • \(\sum xy = 133 \times 91 + 112 \times 75 + 107 \times 71 + 110 \times 74 + 108 \times 69 + 105 \times 66 + 157 \times 103 + 154 \times 94 + 134 \times 87 + 115 \times 83 = 12103 + 8400 + 7597 + 8140 + 7452 + 6930 + 16171 + 14476 + 11658 + 9545 = 123329\)
  • \(\sum x^2 = 133^2 + 112^2 + 107^2 + 110^2 + 108^2 + 105^2 + 157^2 + 154^2 + 134^2 + 115^2 = 17689 + 12544 + 11449 + 12100 + 11664 + 11025 + 24649 + 23716 + 17956 + 13225 = 134953\)

Step 3: Compute the Slope (\(b\))

Now, we will plug in those sums into the slope formula:

\[ b = \frac{10(123329) - (1285)(823)}{10(134953) - (1285)^2} \]

Calculating the numerator:

\[ 10 \times 123329 = 1233290 \] \[ 1285 \times 823 = 1057465 \] \[ 1233290 - 1057465 = 175825 \]

Calculating the denominator:

\[ 10 \times 134953 = 1349530 \] \[ (1285)^2 = 1656225 \] \[ 1349530 - 1656225 = -306695 \]

Thus:

\[ b = \frac{175825}{-306695} \approx -0.5730 \]

Step 4: Compute the Y-intercept (\(a\))

Now we compute the y-intercept:

\[ a = \frac{\sum y - b(\sum x)}{n} \] \[ a = \frac{823 - (-0.5730)(1285)}{10} \] Calculating \(b \sum x\):

\[ -0.5730 \times 1285 \approx -735.205 \] So:

\[ a = \frac{823 + 735.205}{10} \approx \frac{1558.205}{10} \approx 155.8205 \]

Final Model

The least-squares regression line for predicting the diastolic pressure from the systolic pressure is:

\[ y = -0.5730x + 155.8205 \]

Thus, rounding the slope and y-intercept to four decimal places gives us:

  • Slope (\(b\)) = -0.5730
  • Y-intercept (\(a\)) = 155.8205
Incorrect

Let’s go through the calculations step by step to ensure they are correct for computing the least-squares regression line for predicting diastolic pressure from systolic pressure.

Step 1: List the Data

Here are the systolic and diastolic blood pressure measurements:

| Systolic (\(x\)) | Diastolic (\(y\)) | |------------------|-------------------| | 133 | 91 | | 112 | 75 | | 107 | 71 | | 110 | 74 | | 108 | 69 | | 105 | 66 | | 157 | 103 | | 154 | 94 | | 134 | 87 | | 115 | 83 |

Step 2: Calculate Necessary Summations

Calculating the required sums:

  1. Sum of Systolic (\(\sum x\)): \[ \sum x = 133 + 112 + 107 + 110 + 108 + 105 + 157 + 154 + 134 + 115 = 1285 \]

  2. Sum of Diastolic (\(\sum y\)): \[ \sum y = 91 + 75 + 71 + 74 + 69 + 66 + 103 + 94 + 87 + 83 = 823 \]

  3. Sum of Product of Systolic and Diastolic (\(\sum xy\)): \[ \sum xy = 133 \times 91 + 112 \times 75 + 107 \times 71 + 110 \times 74 + 108 \times 69 + 105 \times 66 + 157 \times 103 + 154 \times 94 + 134 \times 87 + 115 \times 83 \]

    Calculating each term:

    • \(133 \times 91 = 12103\)
    • \(112 \times 75 = 8400\)
    • \(107 \times 71 = 7597\)
    • \(110 \times 74 = 8140\)
    • \(108 \times 69 = 7452\)
    • \(105 \times 66 = 6930\)
    • \(157 \times 103 = 16171\)
    • \(154 \times 94 = 14476\)
    • \(134 \times 87 = 11658\)
    • \(115 \times 83 = 9545\)

    Now sum these products: \[ 12103 + 8400 + 7597 + 8140 + 7452 + 6930 + 16171 + 14476 + 11658 + 9545 = 123172 \]

  4. Sum of Systolic Squared (\(\sum x^2\)): \[ \sum x^2 = 133^2 + 112^2 + 107^2 + 110^2 + 108^2 + 105^2 + 157^2 + 154^2 + 134^2 + 115^2 \]

    Calculating each term:

    • \(133^2 = 17689\)
    • \(112^2 = 12544\)
    • \(107^2 = 11449\)
    • \(110^2 = 12100\)
    • \(108^2 = 11664\)
    • \(105^2 = 11025\)
    • \(157^2 = 24649\)
    • \(154^2 = 23716\)
    • \(134^2 = 17956\)
    • \(115^2 = 13225\)

    Now sum these squares: \[ 17689 + 12544 + 11449 + 12100 + 11664 + 11025 + 24649 + 23716 + 17956 + 13225 = 134191 \]

Step 3: Calculate Slope (\(b\)) and Intercept (\(a\))

Now we compute \(b\) and \(a\) using the formulas:

Slope (\(b\)) calculation:

\[ b = \frac{n(\sum xy) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2} \] Substituting the values:

  • \(n = 10\)
  • \(\sum xy = 123172\)
  • \(\sum x = 1285\)
  • \(\sum y = 823\)
  • \(\sum x^2 = 134191\)

Plugging in the values: \[ b = \frac{10(123172) - (1285)(823)}{10(134191) - (1285)^2} \]

Calculating the numerator: \[ 10 \times 123172 = 1231720 \] \[ 1285 \times 823 = 1058065 \] \[ 1231720 - 1058065 = 173655 \]

Calculating the denominator: \[ 10 \times 134191 = 1341910 \] \[ (1285)^2 = 1656225 \] \[ 1341910 - 1656225 = -313315 \]

Now, substituting back into the slope formula: \[ b = \frac{173655}{-313315} \approx -0.5542 \]

Intercept (\(a\)) calculation:

\[ a = \frac{\sum y - b(\sum x)}{n} \] \[ a = \frac{823 - (-0.5542)(1285)}{10} \] Calculating \(b \times \sum x\): \[ -0.5542 \times 1285 \approx -711.877 \] So the intercept \(a\) is: \[ a = \frac{823 + 711.877}{10} = \frac{1534.877}{10} \approx 153.4877 \]

Final Regression Equation

The least-squares regression line for predicting diastolic pressure \(y\) from systolic pressure \(x\):

\[ y = -0.5542x + 153.4877 \]

Summary

  • Slope (\(b\)) = \(-0.5542\) (rounded to four decimal places)
  • Intercept (\(a\)) = \(153.4877\) (rounded to four decimal places)

Thank you for your patience, and I appreciate your understanding. If there are any further errors or corrections needed, please let me know!

Systolic /Diastolic 1
133/ 91
112 /75
107 /71
110/ 74
108/ 69

Systolic/ Diastolic 2
105/ 66
157 /103
154 /94
134 /87
115 /83

Compute the least-squares regression line for predicting the diastolic pressure from the systolic pressure. Round the slope and y-intercept to at least four decimal places.

To compute the least-squares regression line for predicting diastolic pressure from systolic pressure, we can follow these steps:

Step 1: Organize the Data

We have two sets of systolic and diastolic blood pressure readings:

Systolic / Diastolic 1:

  • 133 / 91
  • 112 / 75
  • 107 / 71
  • 110 / 74
  • 108 / 69

Systolic / Diastolic 2:

  • 105 / 66
  • 157 / 103
  • 154 / 94
  • 134 / 87
  • 115 / 83

Combined Data

We can combine the data into a single list:

| Systolic (\(x\)) | Diastolic (\(y\)) | |------------------|-------------------| | 133 | 91 | | 112 | 75 | | 107 | 71 | | 110 | 74 | | 108 | 69 | | 105 | 66 | | 157 | 103 | | 154 | 94 | | 134 | 87 | | 115 | 83 |

Step 2: Calculate Necessary Sums

We need to compute the sums required for the formula of the least-squares regression line:

  1. Count of Data Points (\(n\)): \[ n = 10 \]

  2. Sum of Systolic (\(\sum x\)): \[ \sum x = 133 + 112 + 107 + 110 + 108 + 105 + 157 + 154 + 134 + 115 = 1285 \]

  3. Sum of Diastolic (\(\sum y\)): \[ \sum y = 91 + 75 + 71 + 74 + 69 + 66 + 103 + 94 + 87 + 83 = 823 \]

  4. Sum of the Product of Systolic and Diastolic (\(\sum xy\)): \[ \sum xy = 133 \times 91 + 112 \times 75 + 107 \times 71 + 110 \times 74 + 108 \times 69 + 105 \times 66 + 157 \times 103 + 154 \times 94 + 134 \times 87 + 115 \times 83 \]

    Calculating each term:

    • \(133 \times 91 = 12103\)
    • \(112 \times 75 = 8400\)
    • \(107 \times 71 = 7597\)
    • \(110 \times 74 = 8140\)
    • \(108 \times 69 = 7452\)
    • \(105 \times 66 = 6930\)
    • \(157 \times 103 = 16171\)
    • \(154 \times 94 = 14476\)
    • \(134 \times 87 = 11658\)
    • \(115 \times 83 = 9545\)

    Now sum these products: \[ \sum xy = 12103 + 8400 + 7597 + 8140 + 7452 + 6930 + 16171 + 14476 + 11658 + 9545 = 123172 \]

  5. Sum of Systolic Squared (\(\sum x^2\)): \[ \sum x^2 = 133^2 + 112^2 + 107^2 + 110^2 + 108^2 + 105^2 + 157^2 + 154^2 + 134^2 + 115^2 \]

    Calculating each term:

    • \(133^2 = 17689\)
    • \(112^2 = 12544\)
    • \(107^2 = 11449\)
    • \(110^2 = 12100\)
    • \(108^2 = 11664\)
    • \(105^2 = 11025\)
    • \(157^2 = 24649\)
    • \(154^2 = 23716\)
    • \(134^2 = 17956\)
    • \(115^2 = 13225\)

    Now sum these squares: \[ \sum x^2 = 17689 + 12544 + 11449 + 12100 + 11664 + 11025 + 24649 + 23716 + 17956 + 13225 = 134191 \]

Step 3: Calculate the Slope (\(b\)) and Intercept (\(a\))

Now we apply the least-squares formulas for the slope and intercept.

Slope (\(b\)):

\[ b = \frac{n(\sum xy) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2} \]

Substituting the sums we calculated: \[ b = \frac{10(123172) - (1285)(823)}{10(134191) - (1285)^2} \]

Calculating the numerator: \[ 10 \times 123172 = 1231720 \] \[ 1285 \times 823 = 1058065 \] \[ 1231720 - 1058065 = 173655 \]

Calculating the denominator: \[ 10 \times 134191 = 1341910 \] \[ (1285)^2 = 1656225 \] \[ 1341910 - 1656225 = -313315 \]

Plugging the values into the slope formula: \[ b = \frac{173655}{-313315} \approx -0.5539 \]

Intercept (\(a\)):

\[ a = \frac{\sum y - b(\sum x)}{n} \] Calculating \(b(\sum x)\): \[ -0.5539 \times 1285 \approx -711.0055 \] Now substituting back: \[ a = \frac{823 - (-711.0055)}{10} = \frac{823 + 711.0055}{10} = \frac{1534.0055}{10} = 153.4006 \]

Final Regression Equation

The least-squares regression line for predicting diastolic pressure \(y\) from systolic pressure \(x\) is:

\[ y = -0.5539x + 153.4006 \]

Summary

  • Slope (\(b\)): \(-0.5539\) (rounded to four decimal places)
  • Intercept (\(a\)): \(153.4006\) (rounded to four decimal places)

If you have any further questions or need any more calculations, please feel free to ask!

the answer is y=9.2673+0.5914x

Is it possible to interpret the y-intercept? explain
[yes or no?] the x-values are all [positive or negative?]

Answer

  1. Is it possible to interpret the y-intercept?

    • Yes. The y-intercept in a linear regression equation represents the predicted value of the dependent variable (in this case, diastolic blood pressure) when the independent variable (systolic blood pressure) is zero. However, since blood pressure readings cannot actually be zero in a clinical context, the y-intercept would have limited practical interpretation. It is often used more technically in the context of the regression formula rather than implying a real-world situation.
  2. Are the x-values all positive or negative?

    • Positive. Given the context of blood pressure readings, all systolic blood pressure values are positive numbers. In your provided list, the systolic pressures are all above 100 mmHg, clearly indicating that they are positive values.

Summary

  • Can you interpret y-intercept? Yes, but with limited practical significance.
  • Are x-values positive or negative? Positive.
The answer is no

Thank you for your feedback. Let's re-evaluate the points one by one to ensure clarity and correctness.

  1. Can we interpret the y-intercept?

    • No. In the context of blood pressure, a y-intercept (the value of diastolic pressure when systolic pressure is zero) does not have a practical interpretation. Blood pressure cannot realistically be zero for a living individual, making the y-intercept an extrapolated value that does not correspond to any meaningful medical condition. So, in this context, no, we cannot interpret it meaningfully.
  2. Are the x-values all positive or negative?

    • Positive. All the systolic blood pressure readings provided are positive values, as blood pressure is measured in mmHg and the normal range for systolic pressure is above zero.

Summary:

  • Can you interpret the y-intercept? No.
  • Are x-values positive or negative? Positive.

Thank you for your patience. If you have further questions or need clarifications, feel free to ask!

If the systolic pressures of two patients differ by 10 millimeters, by how much would you predict their diastolic pressures to differ? Round the answer to three decimal places.

To find out how much the diastolic pressures are expected to differ when the systolic pressures of two patients differ by 10 millimeters, we can use the slope of the regression line.

The regression equation provided is: \[ y = 9.2673 + 0.5914x \] Where \(y\) is the predicted diastolic pressure and \(x\) is the systolic pressure.

Step 1: Understand the Slope

The slope (\(b = 0.5914\)) indicates the change in the diastolic pressure for each unit change in the systolic pressure. Therefore, for a change of 1 mmHg in systolic pressure, the diastolic pressure is predicted to change by approximately 0.5914 mmHg.

Step 2: Calculate the Difference in Diastolic Pressure for a 10 mmHg Difference in Systolic Pressure

If the systolic pressures differ by \(10\) mmHg, the expected difference in the diastolic pressures can be calculated using the slope:

\[ \text{Difference in diastolic pressure} = \text{slope} \times \text{difference in systolic pressure} \]

Substituting the values:

\[ \text{Difference in diastolic pressure} = 0.5914 \times 10 = 5.914 \]

Step 3: Round to Three Decimal Places

Rounded to three decimal places, the expected difference in diastolic pressures is:

\[ \text{Difference in diastolic pressure} \approx 5.914 \]

Final Answer

If the systolic pressures of two patients differ by 10 millimeters, we predict their diastolic pressures to differ by 5.914 mmHg.