A block with a mass of m = 31 kg rests on a frictionless surface and is subject to two forces acting on it. The first force is directed in the negative x-direction with a magnitude of F1 = 11 N. The second has a magnitude of F2 = 22.75 N and acts on the body at an angle θ = 15° up from the horizontal, as shown.

Question

A. Write an expression for the component of net force, Fnet,x, in the x direction, in terms of the variables given in the problem statement.

B. Write an expression for the magnitude of the normal force, FN, acting on the block, in terms of F2, and the other variables of the problem . Assume that the surface it rest on is rigid. FN=?

C. Find the block's acceleration in the x direction, ax, in meters per square second. ax=

I am completely stock tried almost everything but not getting the right answer !!!!

Answer 1

a)Fnetx=F2cos(theta)-F1
b)FN=F2sin(theta)+mg
c)i don't know

Answer 2

Part C)
F = ma
a = F/m
acceleration = Fnetx / 31