(a) It equals the component of g along the direction of motion.
That would be 9.8 sin16.3 m/s^2
(b) The vertical drop is
H = 2.00 sin 16.3 = 0.561 m
Conservation of energy tells you that, with no friction,
V^2 = 2 g H after falling a vertical distance H
A block starts from rest at the top of a 2.00-m long, 16.3 -degree frictionless
incline.
(a) What is the acceleration (m/s2 ) of the block?
(b) How fast (m/s) is it going at the bottom?
1 answer
1 answer