A block of wood with a mass of 4.62 kg sits on the edge of a table that is 0.99 m tall. A bullet with a mass of 70.5 g traveling with a speed of 450 m/s is shot into the block and is lodged in it. Assuming that no energy is lost to friction, how far from the table will the block land?

Answer 1

conservation of momentum applies to the block/bullet.

MbVb=(Mb+Mblock)Vf

now find out how much time it takes to fall .99m
Then, distance=Vf*timetofall