A block of wood of mass 1.2kg initially at rest is free to slide on a horizontal surface. A bullet of mass 100g travelling at a speed of 780ms^-1 is fired horizontally at the block and becomes embedded in it. Calculate the speed the block and bullet move off at immediately after the collision.

Answer 1

conservation of momentum

massbullet*velocitybullet=(massbullet+massblock)V
solve for V

Answer 2

v=1.67