m2 going up is +
-m1 g + m2 g sin T= (m1+m2)a
-2.5(9.8)+9.8m2 sin T=-(2.5+m2).108
-.8(9.8)+9.8m2sinT = (.8+m2)2.888
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subtract to get rid of 9.8m2 sin T
solve result for m2
go back and get m2 sinT and therefore sin T
A block of mass m1 hangs vertically and is attached by a string to a block of mass m2 on a frictionless slope inclined at angle theta to the horizontal, as shown above. If m1 =
2.5 kg, it accelerates at -0.108 m/s2. If m1 = 0.8 kg, it accelerates at 2.888 m/s2.
Determine the angle theta and m2.
1 answer