1.93*10^2 = (17.4 +22.7) a
solve for a
use that a for part two
F = tension = 17.4 * a
A block of mass m1 = 17.4 kg is on a frictionless table to the left of the second block of mass m2 = 22.7 kg, attached by a horizontal string.
If a horizontal force of 1.93 ✕ 102 N is exerted on the block m2 in the positive x-direction, find the acceleration (in m/s2) of the two blocks.
What is the tension (in N) in the string connecting the blocks?
2 answers
4.81
2 answers