A block of mass m = 3.20kg slides from rest a distance d down a frictionless incline at angle θ = 30.0° where it runs into a spring of spring constant 425 N/m. When the block momentarily stops, it has compressed the spring by 22.0 cm.
(a) What is the distance d?
I found this to be 0.436 meters.
(b) What is the distance between the point of first contact and the point where the block's speed is greatest?
Okay, here is my work:
kx=Mg(d+x)sin30
425x=(3.2)(9.8)(.436+x)sin30
425x=15.68(.436+x)
425x=6.83648+15.68x
409.32x=6.83648
x=59.8729 m
And then, converted to cm (as required) would be 5987.29. Is this correct?
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