first of all, look at the block on the incline.
The normal force is mgCosTheta
the friction force then is mu*mg*CosTheta
The portion of the block weight that is going down the incline is mgSinTheta.
initial KE=workdonegoingup slope
1/2 m v^2=(mu*mgCosTheta+mgSinTheta)d
solve all that for d.
A block of mass is moving along the horizontal frictionless surface with a speed of 5.70 m/s. If the slope is 11.0° and the coefficient of kinetic friction between the block and the incline is 0.260, how far does the block travel up the incline? Show step by step please! Thanks!!
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