A block of mass 50 kg is pulled on a frictionless floor by F=210N directed to 30angle horizontally, If the block moves 3m, find work done?

a. 115 √2J
b. 315 √3J

Answer is B 315 √3J , my question is how to solve it in this way i mean, i solved it like this,
w=fdcostheta.
210X3 cos(30)
which is equal to 543.8639536 , i.e 315 √3J
but without calculator how to write 315 √3J from 543.863953, solve it please thanks.