ok, i read this as the 3 kg is on the horizontal surface, the 2kg is pulling it.
F=ma
2g=(2+3)a
solve for.
then,
d=1/2 a t^2
.8=1/2 a:(above) * t^2 solve for time t.
a block of mass 3 kg rests on a smooth table and connected to another block of mass 2 kg, after passing over and ideal pulley, the block of mass 2 kg is released. how long does it take the block to travel 80 cm
2 answers
0.639