the horizontal component of P (along the rod) is [P * cos(30º)]
the vertical component is [P * sin(30º)]
the normal reaction is the block's weight (m * g), minus the vertical component of P
you surmise correctly re: the result of P exceeding 392 Newtons
A block of mass 20kg rests on a smooth horizontal ground near to a fixed post, to which it is attached to a light, horizontal rod. The block is pulled away from the post by force PN inclined at 30 degrees to the horizontal.
Find in terms of P, the tension of the rod and the normal reaction between the block and the ground.
Explain what would happen if the value of p exceeded 392.
I know that b is something like the block would lift of the ground but do not know how to do part a
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