a block of mass 2.50 kg rests on a ramp. if the coefficient of static friction between the block and ramp is 0.350, what maximum angle can the ramp make with the horizontal before the block starts to slip down?

Answer 1

F = 2.50 * 9.8 = 24.5N @ A deg.

Fp = 24.5*sinA = Force parallel with plane.

Fv = 24.5*cosA = Force perpendicular to
plane.

uFv = 0.35Fv = Force of friction.

Fp - 0.35Fv = ma,
a = 0(block at rest),
Fp -0.35Fv = 0,
Fp = 0.35Fv,
24.5*sinA = 0.35*24.5*cosA,
Divide both sides by 24.5:
sinA = 0.35*cosA
Divide both sides by cosA:
sinA / cosA = 0.35,
sinA / cosA = TanA,
TanA = 0.35,
A = 19.3deg.

Answer 2

answer

Answer 3

show me the steps on the calculation to the final answer

Answer 4

Meaning of fv,fp

Answer 5

Fp and fv their meanings