x = .0991 meter
energy stored = (1/2)(87.5)(.0991)^2
friction force = mu m g = mu * .941*9.81
so
mu*.941*9.81*.528 = (1/2)(87.5)(.0991)^2
A block of mass 0.941 kg is kept at rest as i compresses a horizontal mass-less spring (K=87.5 N/m) by 9.91 cm. As the block is released, it travels 0.528 m on a rough horizontal surface before stopping.
The acceleration of gravity is 9.8 m/s^2.
Calculate the coefficient of kinetic friction between surface and block.
1 answer