A block of mass 0.25 kg is connected to a spring with spring constant 35 N/m. The block is oscillating on a frictionless horizontal surface. Its speed as it passes through its equilibrium position is 1.04 m/s. What's the total energy of the system?

Answer 1

The total energy is entirely kinetic energy as the block passes through the equilibrium position

E = 1/2*m*v^2

where m is the mass, and v is the velocity