a block of mass 0.1kg is attached to spring and placed on a horizontal frictionless table .the spring is stretched 20cm when a force of 5n is applied.calculate the spring constant
3 answers
force / distance
F=kx
K=5/0.2=50/2=25N/M
T=2π✓m/K
T=2×3.142✓0.1/25
T=6.284×0.0632
T=0.397Sec
K=5/0.2=50/2=25N/M
T=2π✓m/K
T=2×3.142✓0.1/25
T=6.284×0.0632
T=0.397Sec
Yes
1 answer