A block of aluminum has the following measurements:  

Length 3.6 cm
Width 2.3 cm
Height 2.2 cm
mass 50g
Calculate the density of the material.

Give the volume formula, and show your work.

Give the density formula and show your work.

State your answer and include correct units.

3 answers

To calculate the density of the aluminum block, we need to follow these steps:

Step 1: Calculate the Volume

Volume Formula:

The formula for the volume \( V \) of a rectangular block is given by:

\[ V = \text{Length} \times \text{Width} \times \text{Height} \]

Substituting the Measurements:

Given:

  • Length = 3.6 cm
  • Width = 2.3 cm
  • Height = 2.2 cm

Now substitute these values into the formula:

\[ V = 3.6 , \text{cm} \times 2.3 , \text{cm} \times 2.2 , \text{cm} \]

Calculating the volume:

\[ V = 3.6 \times 2.3 \times 2.2 = 18.552 , \text{cm}^3 \]

Step 2: Calculate the Density

Density Formula:

The formula for density \( \rho \) is given by:

\[ \rho = \frac{\text{mass}}{\text{volume}} \]

Substituting the Values:

Given:

  • Mass = 50 g
  • Volume = 18.552 cm³

Now substitute these values into the formula:

\[ \rho = \frac{50 , \text{g}}{18.552 , \text{cm}^3} \]

Calculating the density:

\[ \rho \approx 2.698 , \text{g/cm}^3 \]

Final Answer

The density of the aluminum block is approximately:

\[ \boxed{2.70 , \text{g/cm}^3} \]

(Note: The answer is rounded to two decimal places.)

simplify

Let's simplify the calculations and results for the density of the aluminum block in a clear and concise manner.

Step 1: Calculate the Volume

Volume Formula:

\[ V = \text{Length} \times \text{Width} \times \text{Height} \]

Using the measurements:

  • Length = 3.6 cm
  • Width = 2.3 cm
  • Height = 2.2 cm

Calculating the volume:

\[ V = 3.6 , \text{cm} \times 2.3 , \text{cm} \times 2.2 , \text{cm} = 18.552 , \text{cm}^3 \]

Step 2: Calculate the Density

Density Formula:

\[ \rho = \frac{\text{mass}}{\text{volume}} \]

Using the given mass:

  • Mass = 50 g
  • Volume = 18.552 cm³

Calculating the density:

\[ \rho = \frac{50 , \text{g}}{18.552 , \text{cm}^3} \approx 2.698 , \text{g/cm}^3 \]

Final Answer

The density of the aluminum block is approximately:

\[ \boxed{2.70 , \text{g/cm}^3} \]

This version simplifies the presentation while retaining all the necessary information for clarity.