A block is projected up a frictionless inclined plane with initial speed v0 = 2.19 m/s. The angle of incline is θ = 25.1°. (a) How far up the plane does it go? (b) How long does it take to get there? (c) What is its speed when it gets back to the bottom?

Answer 1

Vo = 2.19m/s[25.1o].
Yo = 2.19*sin25.1 = 0.93 m/s.

a. Y^2 = Yo^2 + 2g*h = 0, 0.93^2 - 19.6h = 0, -19.6h = -0.865, h = 0.0441 m.

b. Y = Yo + g*t = 0, 0.93 - 9.8t = 0, -9.8t = -0.93, t = 0.095 s.

c. V = Vo = 2.19 m/s.