normal force = m g cos T
force holding block = .4 m g cos T
force of gravity down slope = m g sin T
so
.4 cos T = sin T
so
tan T = .4
T = 21.8 degrees
A block is at rest on the incline shown in the
figure. The coefficients of static and kinetic
friction are µs = 0.4 and µk = 0.34, respectively.
The acceleration of gravity is 9.8 m/s.
What is the largest angle which the incline
can have so that the mass does not slide down
the incline?
Answer in units of degrees
1 answer