mgh₁=mv₁²/2
mgh₂=mv₂²/2= m(3.9v₁)²/2=15.21 mv₁²/2
h₂=15.21h₁
A block initially at rest is allowed to slide
down a frictionless ramp and attains a speed
v at the bottom.
To achieve a speed 3.9 v at the bottom, how
many times as high
h2
h1
must a new ramp be?
2 answers
ur mom