A block and tackle with a velocity ratio of 6 is used to lift a load of mass 30kg through a vertical distance of 40cm at a steady rate. If the effort is 60newtons, determine the loss in energy.

Answer 1

Work accomplished = 30 * 0.4 * g = 12 * 9.8 Joules =118 Joules

Work in = 60 * 0.4 * 6 = 144 Joules

so 144 - 118 Joules