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A bird watcher meanders through the woods, walking 1.10 km due east, 0.624 km due south, and 1.09 km in a direction 18.2 ° nort...Asked by bill
A bird watcher meanders through the woods, walking 0.544 km due east, 0.925 km due south, and 3.58 km in a direction 17.3 ° north of west. The time required for this trip is 1.957 h. Determine the magnitudes of the bird watcher's (a) displacement and (b) average velocity.
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Answered by
Steve
0.544 km E = <0.544,0.000>
0.925 km S = <0.000,-0.925>
3.58 km W17.3°N = <-3.418,1.065>
Adding them all up, the final location is <-2.874,0.140>
Now you should be able to figure the final displacement and thus the average velocity.
0.925 km S = <0.000,-0.925>
3.58 km W17.3°N = <-3.418,1.065>
Adding them all up, the final location is <-2.874,0.140>
Now you should be able to figure the final displacement and thus the average velocity.
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