The bird's initial altitude is 10 meters above the ground, and after 3 seconds, it settles on a branch that is 3 meters above the ground. So, the bird descended 10-3=<<10-3=7>>7 meters in 3 seconds.
Now, let's calculate the rate of change in the bird's altitude. The quotient that represents the rate of change is found by dividing the change in altitude (7 meters) by the change in time (3 seconds).
Rate of change = Change in altitude / Change in time = 7 meters / 3 seconds
Calculating this quotient gives us the rate of change in the bird's altitude as approximately 2.33 meters per second.
Therefore, the bird's altitude is descending at a rate of 2.33 meters per second.
a bird is flying at an average altitude of 10 meters above the ground. after 3 seconds it settles on a branch that is 3 meters above the ground. interpret the quotient to describe the rate of change in the birds altitude. Give your answer to the nearest hundredth and remember that the bird is descending
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