A bird is flying at an average altitude of 10 meters above the ground. After seconds, it settles on a branch that is 3 meters above the ground interpret the quotient to describe the rate or change in the bird's altitude.

Answer 1

The quotient in this case refers to the change in the bird's altitude over time: (10m - 3m) / t seconds. This describes the rate at which the bird lowers its altitude. It states that per second, the bird is losing (10m - 3m) / t meters in altitude. Depending on the value of t, it will give us the speed at which the bird is lowering its altitude per second. The smaller t, the faster the bird is dropping in altitude, and the larger t, the slower.