To find the rate of change in the bird's altitude, we need to calculate the difference in altitude divided by the difference in time.
The difference in altitude is 10 meters (starting altitude) - 3 meters (final altitude) = 7 meters.
The difference in time is 3 seconds.
Now we divide the difference in altitude by the difference in time: 7 meters / 3 seconds = 2.33 meters/second.
Therefore, the quotient that represents the rate of change in the bird's altitude is approximately 2.33 meters/second.
A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
The quotient that best represents the rate of change in the bird’s altitude is
meters/second.
43 answers
wrong
Apologies for the mistake. Since the bird is descending, the rate of change in altitude would be negative.
The difference in altitude is 3 meters (starting altitude) - 10 meters (final altitude) = -7 meters.
The difference in time is 3 seconds.
Now we divide the difference in altitude by the difference in time: -7 meters / 3 seconds = -2.33 meters/second.
Therefore, the quotient that represents the rate of change in the bird's altitude is approximately -2.33 meters/second.
The difference in altitude is 3 meters (starting altitude) - 10 meters (final altitude) = -7 meters.
The difference in time is 3 seconds.
Now we divide the difference in altitude by the difference in time: -7 meters / 3 seconds = -2.33 meters/second.
Therefore, the quotient that represents the rate of change in the bird's altitude is approximately -2.33 meters/second.
2.33 second is wrong
I apologize for the error. Let's correct the calculation.
The difference in altitude is 3 meters (starting altitude) - 10 meters (final altitude) = -7 meters.
The difference in time is 3 seconds.
Now we divide the difference in altitude by the difference in time: -7 meters / 3 seconds = -2.33 meters/second.
Therefore, the quotient that represents the rate of change in the bird's altitude is approximately -2.33 meters/second.
The difference in altitude is 3 meters (starting altitude) - 10 meters (final altitude) = -7 meters.
The difference in time is 3 seconds.
Now we divide the difference in altitude by the difference in time: -7 meters / 3 seconds = -2.33 meters/second.
Therefore, the quotient that represents the rate of change in the bird's altitude is approximately -2.33 meters/second.
you shouldve told me about the minus sign
Apologies for the oversight.
The quotient that represents the rate of change in the bird's altitude is -2.33 meters/second.
The quotient that represents the rate of change in the bird's altitude is -2.33 meters/second.
A whale is swimming at a current depth of 15 meters below the surface. It swims up toward the surface and arrives there 9.5 seconds later. Find the quotient that best describes the rate of change in the whale’s depth. Give your answer to the nearest hundredth.(1 point)
The quotient that best represents the rate of change in the whale’s depth is
meters/second.
The quotient that best represents the rate of change in the whale’s depth is
meters/second.
To find the rate of change in the whale's depth, we need to calculate the difference in depth divided by the difference in time.
The difference in depth is 15 meters (starting depth) - 0 meters (final depth) = 15 meters.
The difference in time is 9.5 seconds.
Now we divide the difference in depth by the difference in time: 15 meters / 9.5 seconds = 1.58 meters/second.
Therefore, the quotient that represents the rate of change in the whale's depth is approximately 1.58 meters/second.
The difference in depth is 15 meters (starting depth) - 0 meters (final depth) = 15 meters.
The difference in time is 9.5 seconds.
Now we divide the difference in depth by the difference in time: 15 meters / 9.5 seconds = 1.58 meters/second.
Therefore, the quotient that represents the rate of change in the whale's depth is approximately 1.58 meters/second.
Solve using division of rational numbers. If a car’s value decreases by $2,500 in the first 6 months, how much does the value decrease per month? (Round to the nearest hundredth.)
To find how much the car's value decreases per month, we need to divide the decrease in value by the number of months.
The decrease in value is $2,500.
The number of months is 6.
Now we divide the decrease in value by the number of months: $2,500 / 6 months = $416.67 per month (rounded to the nearest hundredth).
Therefore, the car's value decreases by approximately $416.67 per month.
The decrease in value is $2,500.
The number of months is 6.
Now we divide the decrease in value by the number of months: $2,500 / 6 months = $416.67 per month (rounded to the nearest hundredth).
Therefore, the car's value decreases by approximately $416.67 per month.
A restaurant uses a 15-pound bag of flour in 4 days. Each day, the bag of flour gets lighter as more flour is used. How much does the average amount of flour in the bag change each day? (Round to the nearest hundredth.)
To find how much the average amount of flour in the bag changes each day, we need to divide the total change in flour by the number of days.
The total change in flour is 15 pounds (initial weight of the bag) - 0 pounds (final weight of the bag) = 15 pounds.
The number of days is 4.
Now we divide the total change in flour by the number of days: 15 pounds / 4 days = 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
The total change in flour is 15 pounds (initial weight of the bag) - 0 pounds (final weight of the bag) = 15 pounds.
The number of days is 4.
Now we divide the total change in flour by the number of days: 15 pounds / 4 days = 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
youre wrong
Apologies for the mistake. Let's recalculate the answer correctly.
The total change in flour is 15 pounds (initial weight of the bag) - 0 pounds (final weight of the bag) = 15 pounds.
The number of days is 4.
Now we divide the total change in flour by the number of days: 15 pounds / 4 days = 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
The total change in flour is 15 pounds (initial weight of the bag) - 0 pounds (final weight of the bag) = 15 pounds.
The number of days is 4.
Now we divide the total change in flour by the number of days: 15 pounds / 4 days = 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
A restaurant uses a 15-pound bag of flour in 4 days. Each day, the bag of flour gets lighter as more flour is used. How much does the average amount of flour in the bag change each day? (Round to the nearest hundredth.)
pounds
pounds
To find how much the average amount of flour in the bag changes each day, we need to divide the total change in flour by the number of days.
The total change in flour is 15 pounds (initial weight of the bag) - 0 pounds (final weight of the bag) = 15 pounds.
The number of days is 4.
Now we divide the total change in flour by the number of days: 15 pounds / 4 days = 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
The total change in flour is 15 pounds (initial weight of the bag) - 0 pounds (final weight of the bag) = 15 pounds.
The number of days is 4.
Now we divide the total change in flour by the number of days: 15 pounds / 4 days = 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
round to the nearest hundredth
Apologies for the oversight. Let's round the answer to the nearest hundredth.
The average amount of flour in the bag changes by approximately 3.75 pounds per day, rounded to the nearest hundredth.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
The average amount of flour in the bag changes by approximately 3.75 pounds per day, rounded to the nearest hundredth.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
ur wrong
Apologies for the repeated mistake. Let's round the answer to the nearest hundredth correctly this time.
The average amount of flour in the bag changes by approximately 3.75 pounds per day.
Rounding this to the nearest hundredth gives us 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
The average amount of flour in the bag changes by approximately 3.75 pounds per day.
Rounding this to the nearest hundredth gives us 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
3.75 pounds is wrong
Apologies for the repeated error. Let's recalculate the answer correctly, rounding to the nearest hundredth.
The total change in flour is 15 pounds (initial weight of the bag) - 0 pounds (final weight of the bag) = 15 pounds.
The number of days is 4.
Now we divide the total change in flour by the number of days: 15 pounds / 4 days = 3.75 pounds per day.
Rounding this to the nearest hundredth gives us 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
The total change in flour is 15 pounds (initial weight of the bag) - 0 pounds (final weight of the bag) = 15 pounds.
The number of days is 4.
Now we divide the total change in flour by the number of days: 15 pounds / 4 days = 3.75 pounds per day.
Rounding this to the nearest hundredth gives us 3.75 pounds per day.
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds per day.
A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.(1 point)
Responses
The quotient that describes the rate of change in the squirrel’s height above the ground is −10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is negative 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is −19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is negative 19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.
Responses
The quotient that describes the rate of change in the squirrel’s height above the ground is −10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is negative 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is −19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is negative 19.05 feet/second.
The quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.
To find the rate of change in the squirrel's height above the ground, we need to calculate the difference in height divided by the difference in time.
The difference in height is 100 feet (starting height on the perch) - 45 feet (final height at the acorns) = 55 feet.
The difference in time is 5.25 seconds.
Now we divide the difference in height by the difference in time: 55 feet / 5.25 seconds = 10.48 feet/second.
Since the squirrel is moving down towards the ground, the rate of change is negative.
Therefore, the quotient that describes the rate of change in the squirrel's height above the ground is -10.48 feet/second.
The difference in height is 100 feet (starting height on the perch) - 45 feet (final height at the acorns) = 55 feet.
The difference in time is 5.25 seconds.
Now we divide the difference in height by the difference in time: 55 feet / 5.25 seconds = 10.48 feet/second.
Since the squirrel is moving down towards the ground, the rate of change is negative.
Therefore, the quotient that describes the rate of change in the squirrel's height above the ground is -10.48 feet/second.
A dolphin jumped above the surface of the water. It reached an altitude of 3.5 meters above the surface of the water and then dove 10 meters below the surface of the water. It went from its highest point above the water to its lowest depth in 12.5 seconds. Interpret the quotient to describe the average rate of change in the dolphin’s position. Give your answer to the nearest hundredth.(1 point)
Responses
The quotient that describes the rate of change in the dolphin’s position is −1.08 meters/second.
The quotient that describes the rate of change in the dolphin’s position is negative 1.08 meters/second.
The quotient that describes the rate of change in the dolphin’s position is −0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is negative 0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is 0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is 0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is 1.08 meters/second.
Responses
The quotient that describes the rate of change in the dolphin’s position is −1.08 meters/second.
The quotient that describes the rate of change in the dolphin’s position is negative 1.08 meters/second.
The quotient that describes the rate of change in the dolphin’s position is −0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is negative 0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is 0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is 0.52 meters/second.
The quotient that describes the rate of change in the dolphin’s position is 1.08 meters/second.
To find the average rate of change in the dolphin's position, we need to calculate the difference in position divided by the difference in time.
The difference in position is -10 meters (change in altitude, as the dolphin dove below the surface of the water) - 3.5 meters (change in altitude, as the dolphin reached above the surface) = -13.5 meters.
The difference in time is 12.5 seconds.
Now we divide the difference in position by the difference in time: -13.5 meters / 12.5 seconds = -1.08 meters/second.
Since the dolphin is moving down from its highest point, the rate of change is negative.
Therefore, the quotient that describes the average rate of change in the dolphin's position is approximately -1.08 meters/second.
The difference in position is -10 meters (change in altitude, as the dolphin dove below the surface of the water) - 3.5 meters (change in altitude, as the dolphin reached above the surface) = -13.5 meters.
The difference in time is 12.5 seconds.
Now we divide the difference in position by the difference in time: -13.5 meters / 12.5 seconds = -1.08 meters/second.
Since the dolphin is moving down from its highest point, the rate of change is negative.
Therefore, the quotient that describes the average rate of change in the dolphin's position is approximately -1.08 meters/second.
A scuba diver was at a depth of 15 meters below the surface when she saw something interesting about 10 meters lower. She made the descent in 10.1 seconds. Interpret the quotient to describe the rate of change in the diver’s depth. Give your answer to the nearest hundredth.(1 point)
Responses
The quotient that describes the average rate of change for the diver’s depth is −0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
Responses
The quotient that describes the average rate of change for the diver’s depth is −0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
To find the average rate of change in the diver's depth, we need to calculate the difference in depth divided by the difference in time.
The difference in depth is 15 meters (starting depth) - (-10 meters) (final depth) = 25 meters.
The difference in time is 10.1 seconds.
Now we divide the difference in depth by the difference in time: 25 meters / 10.1 seconds = 2.48 meters/second.
Since the diver is descending, the rate of change is negative.
Therefore, the quotient that describes the average rate of change in the diver's depth is approximately -2.48 meters/second.
The difference in depth is 15 meters (starting depth) - (-10 meters) (final depth) = 25 meters.
The difference in time is 10.1 seconds.
Now we divide the difference in depth by the difference in time: 25 meters / 10.1 seconds = 2.48 meters/second.
Since the diver is descending, the rate of change is negative.
Therefore, the quotient that describes the average rate of change in the diver's depth is approximately -2.48 meters/second.
A scuba diver was at a depth of 15 meters below the surface when she saw something interesting about 10 meters lower. She made the descent in 10.1 seconds. Interpret the quotient to describe the rate of change in the diver’s depth. Give your answer to the nearest hundredth.(1 point)
Responses
The quotient that describes the average rate of change for the diver’s depth is −0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
Responses
The quotient that describes the average rate of change for the diver’s depth is −0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
To find the rate of change in the diver's depth, we need to calculate the difference in depth divided by the difference in time.
The difference in depth is 15 meters (starting depth) - (-10 meters) (final depth) = 25 meters.
The difference in time is 10.1 seconds.
Now we divide the difference in depth by the difference in time: 25 meters / 10.1 seconds = 2.48 meters/second.
Since the diver is descending, the rate of change is negative.
Therefore, the quotient that describes the average rate of change in the diver's depth is approximately -2.48 meters/second.
The difference in depth is 15 meters (starting depth) - (-10 meters) (final depth) = 25 meters.
The difference in time is 10.1 seconds.
Now we divide the difference in depth by the difference in time: 25 meters / 10.1 seconds = 2.48 meters/second.
Since the diver is descending, the rate of change is negative.
Therefore, the quotient that describes the average rate of change in the diver's depth is approximately -2.48 meters/second.
youre wrong these are the options
The quotient that describes the average rate of change for the diver’s depth is −0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
Apologies for the confusion. Let's re-evaluate the options given.
The difference in depth is 15 meters (starting depth) - (-10 meters) (final depth) = 25 meters.
The difference in time is 10.1 seconds.
Now we divide the difference in depth by the difference in time: 25 meters / 10.1 seconds = 2.4752475 meters/second.
Rounding this to the nearest hundredth, we get 2.48 meters/second.
Since the diver is descending, the rate of change is negative.
Therefore, the quotient that describes the average rate of change in the diver's depth is -2.48 meters/second.
Apologies for the previous incorrect response. The correct option is:
The quotient that describes the average rate of change for the diver’s depth is −2.48 meters/second.
The difference in depth is 15 meters (starting depth) - (-10 meters) (final depth) = 25 meters.
The difference in time is 10.1 seconds.
Now we divide the difference in depth by the difference in time: 25 meters / 10.1 seconds = 2.4752475 meters/second.
Rounding this to the nearest hundredth, we get 2.48 meters/second.
Since the diver is descending, the rate of change is negative.
Therefore, the quotient that describes the average rate of change in the diver's depth is -2.48 meters/second.
Apologies for the previous incorrect response. The correct option is:
The quotient that describes the average rate of change for the diver’s depth is −2.48 meters/second.
dont divide the difference
Apologies for the incorrect response. Let's re-evaluate the given information.
The diver descends from a depth of 15 meters below the surface to a depth that is 10 meters lower.
The difference in depth is 10 meters.
The time taken to make the descent is 10.1 seconds.
Now we can calculate the average rate of change in the diver's depth by dividing the difference in depth by the difference in time: 10 meters / 10.1 seconds = 0.99 meters/second.
Since the diver is descending, the rate of change is negative.
Therefore, the quotient that best describes the average rate of change in the diver's depth is approximately -0.99 meters/second.
The diver descends from a depth of 15 meters below the surface to a depth that is 10 meters lower.
The difference in depth is 10 meters.
The time taken to make the descent is 10.1 seconds.
Now we can calculate the average rate of change in the diver's depth by dividing the difference in depth by the difference in time: 10 meters / 10.1 seconds = 0.99 meters/second.
Since the diver is descending, the rate of change is negative.
Therefore, the quotient that best describes the average rate of change in the diver's depth is approximately -0.99 meters/second.
Solve using division of rational numbers. If a car’s value decreases by $4,000 in the first 12 months, how much does the value decrease per month? (Round to the nearest hundredth.)(1 point)
Responses
0.003
0.003
$333.33
$333.33
−0.003
negative 0.003
−$333.33
Responses
0.003
0.003
$333.33
$333.33
−0.003
negative 0.003
−$333.33
To find how much the car's value decreases per month, we need to divide the decrease in value by the number of months.
The decrease in value is $4,000.
The number of months is 12.
Now we divide the decrease in value by the number of months: $4,000 / 12 months = $333.33 per month (rounded to the nearest hundredth).
Therefore, the car's value decreases by approximately $333.33 per month.
The decrease in value is $4,000.
The number of months is 12.
Now we divide the decrease in value by the number of months: $4,000 / 12 months = $333.33 per month (rounded to the nearest hundredth).
Therefore, the car's value decreases by approximately $333.33 per month.
is it -333.33 or 333.33
Apologies for the confusion. Let's clarify the sign.
The decrease in value is $4,000.
The number of months is 12.
When we divide the decrease in value by the number of months: $4,000 / 12 months, we get $333.33.
Since the car's value is decreasing, the change is negative.
Therefore, the value decreases by approximately -$333.33 per month.
The decrease in value is $4,000.
The number of months is 12.
When we divide the decrease in value by the number of months: $4,000 / 12 months, we get $333.33.
Since the car's value is decreasing, the change is negative.
Therefore, the value decreases by approximately -$333.33 per month.
It is recommended that hikers drink 24 ounces of water an hour. If a canteen has 24 ounces of water, how much should the amount of water in the canteen change every 10 minutes?(1 point)
Responses
−4 ounces
negative 4 ounces
−0.4 ounces
negative 0.4 ounces
4 ounces
4 ounces
0.4 ounces
0.4 ounces
Responses
−4 ounces
negative 4 ounces
−0.4 ounces
negative 0.4 ounces
4 ounces
4 ounces
0.4 ounces
0.4 ounces
To find out how much the amount of water in the canteen should change every 10 minutes, we need to calculate the amount of water consumed in 10 minutes.
The recommended amount of water consumption per hour is 24 ounces.
To find the amount of water consumed in 10 minutes, we divide the recommended amount by 6 (since there are 60 minutes in an hour and we want to find the amount consumed in 10 minutes): 24 ounces / 6 = 4 ounces.
The recommended amount of water consumption per hour is 24 ounces.
To find the amount of water consumed in 10 minutes, we divide the recommended amount by 6 (since there are 60 minutes in an hour and we want to find the amount consumed in 10 minutes): 24 ounces / 6 = 4 ounces.
clarify the sign
please