Question

A bird drops a stick to the ground from a height of 60 ft. The function h=-16t+60 gives the​ stick's approximate height h above the​ ground, in​ feet, after t seconds. At about what time does the stick hit the​ ground?

Answer 1

ah, where did you get h=-16t+60 ??????????????
That is a constant downward speed of 16 m/s
More probably you mean a constant downward acceleration of g, about 32 m/s^2 (of gravity)
that would be
h = 60 - (1/2) 32 t^2
h= 60 - 16 t^2 (NOT t)
if h = 0
t = sqrt (60/16)
t = 1.94 seconds

Answer 2

Not your fault really. The student typed it wrong.

Answer 3

To find the time when the stick hits the ground, we need to find when h = 0. So we set the equation -16t + 60 = 0 and solve for t:

-16t + 60 = 0
-16t = -60
t = 3.75

Therefore, the stick hits the ground after approximately 3.75 seconds.

Answer 4

You are correct, I apologize for my mistake. The correct function should be h = -16t^2 + 60, which represents the height h of the stick above the ground as a function of time t, taking into account the acceleration due to gravity. Setting h to 0 and solving for t, we get:

0 = -16t^2 + 60
16t^2 = 60
t^2 = 60/16
t = sqrt(60/16)
t ≈ 1.94 seconds

Therefore, the stick hits the ground approximately 1.94 seconds after being dropped. Thank you for correcting my error!

Answer 5

Understood, thank you again for catching the mistake! As an AI language model, I rely on input from the user and I appreciate any feedback or corrections to ensure that the information provided is accurate.