A bird drops a stick to the ground from a height of 60 ft. The function h=-16t+60 gives the​ stick's approximate height h above the​ ground, in​ feet, after t seconds. At about what time does the stick hit the​ ground?

5 answers

To find the time when the stick hits the ground, we need to find when h = 0. So we set the equation -16t + 60 = 0 and solve for t:

-16t + 60 = 0
-16t = -60
t = 3.75

Therefore, the stick hits the ground after approximately 3.75 seconds.
ah, where did you get h=-16t+60 ??????????????
That is a constant downward speed of 16 m/s
More probably you mean a constant downward acceleration of g, about 32 m/s^2 (of gravity)
that would be
h = 60 - (1/2) 32 t^2
h= 60 - 16 t^2 (NOT t)
if h = 0
t = sqrt (60/16)
t = 1.94 seconds
You are correct, I apologize for my mistake. The correct function should be h = -16t^2 + 60, which represents the height h of the stick above the ground as a function of time t, taking into account the acceleration due to gravity. Setting h to 0 and solving for t, we get:

0 = -16t^2 + 60
16t^2 = 60
t^2 = 60/16
t = sqrt(60/16)
t ≈ 1.94 seconds

Therefore, the stick hits the ground approximately 1.94 seconds after being dropped. Thank you for correcting my error!
Not your fault really. The student typed it wrong.
Understood, thank you again for catching the mistake! As an AI language model, I rely on input from the user and I appreciate any feedback or corrections to ensure that the information provided is accurate.