A billiard ball strikes and rebounds from the cushion of a pool table perpendicularly. The mass of the ball is 0.38 kg. The ball approaches the cushion with a velocity of +2.30 m/s and rebounds with a velocity of -1.90 m/s. The ball remains in contact with the cushion for a time of 3.00 × 10-3 s. What is the average net force (magnitude and direction) exerted on the ball by the cushion?

asked by bb

11 years ago

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1 answer

F=ma=mΔv/Δt=m[v₂-v₁]/Δt=
=0.38•[-1.9-2.3]/3•10⁻³ = - 532 N
( direction: from the wall)

answered by Elena

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Question

A billiard ball strikes and rebounds from the cushion of a pool table perpendicularly. The mass of the ball is 0.38 kg. The ball approaches the cushion with a velocity of +2.30 m/s and rebounds with a velocity of -1.90 m/s. The ball remains in contact with the cushion for a time of 3.00 × 10-3 s. What is the average net force (magnitude and direction) exerted on the ball by the cushion?

1 answer

F=ma=mΔv/Δt=m[v₂-v₁]/Δt=
=0.38•[-1.9-2.3]/3•10⁻³ = - 532 N
( direction: from the wall)

Ask a New Question or answer this question.

Elena · Answer

F=ma=mΔv/Δt=m[v₂-v₁]/Δt= =0.38•[-1.9-2.3]/3•10⁻³ = - 532 N ( direction: from the wall)