A biker covered half the distance between two towns in 2 h 30 min. After that, he increased his speed by 2 km/h . He covered the second half of the distance in 2 h 20 min. Find the distance between the two towns and the initial speed of the biker.​

3 answers

Let's call the distance between the two towns "d" kilometers, and let x be the initial speed of the biker in km/h.

The biker covered half the distance in 2 hours and 30 minutes, which is 2 + 30/60 = 2.5 hours.
Therefore, the time it took the biker to cover the first half of the distance is 2.5 hours.

Using the formula for distance (distance = speed × time), the distance covered in the first half is:
d/2 = x × 2.5

Simplifying, we have:
d/2 = 2.5x

Now, the biker increased his speed by 2 km/h, so his new speed is x + 2 km/h.
He covered the second half of the distance in 2 hours and 20 minutes, which is 2 + 20/60 = 2.33 hours.
Therefore, the time it took the biker to cover the second half of the distance is 2.33 hours.

Using the formula for distance again, the distance covered in the second half is:
d/2 = (x + 2) × 2.33

Simplifying, we have:
d/2 = 2.33x + 4.66

Now, we have two equations:
d/2 = 2.5x
d/2 = 2.33x + 4.66

Multiplying the second equation by 2, we have:
d = 4.66x + 9.32

Now, we can substitute this expression for d in the first equation:
(4.66x + 9.32)/2 = 2.5x

Simplifying, we have:
2.33x + 4.66 = 2.5x
4.66 = 2.5x - 2.33x
4.66 = 0.17x
x = 4.66/0.17
x ≈ 27.41

Therefore, the initial speed of the biker is approximately 27.41 km/h.

Now, we can substitute this value of x in the first equation to find the distance d:
d/2 = 2.5(27.41)
d/2 ≈ 68.52
d ≈ 68.52 × 2
d ≈ 137.04

Therefore, the distance between the two towns is approximately 137.04 kilometers.
AAAaannndd the bot gets it wrong yet again!
Let the distance be 2d, so since distance = speed * time, if his initial speed was v, then
d = 5/2 v
d = 7/3 (v+2)
That means that
5/2 v = 7/3 (v+2)
v = 28 km/hr
Thus, the distance 2d = 2*28 * 2.5 = 140 km
check: 2*30*7/3 = 140 km
Apologies for the incorrect response. Thank you for providing the correct solution.