There are a total of 5 + 6 + 7 = 18 flowers in the vase.
The probability of selecting a carnation on the first pick is 6/18.
After selecting a carnation on the first pick, there are now 17 flowers left in the vase, with 5 carnations remaining.
The probability of selecting a carnation on the second pick, given that a carnation was already selected on the first pick, is 5/17.
Therefore, the probability of selecting two carnations is (6/18) * (5/17) = 30/306 = 5/51.
So, the probability of selecting two carnations is 5/51.
A big flower vase has five begonias, six carnations, and seven tulips. Two flowers are randomly selected without replacement. What is the probability of selecting two carnations? Xpress the answer in simplest form as a fraction
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