The total number of flowers in the vase is 5 + 6 + 7 = 18.
The probability of selecting a carnation on the first draw is 6/18 = 1/3.
After selecting a carnation, there are 17 flowers left in the vase, with 5 carnations remaining.
The probability of selecting a carnation on the second draw is 5/17.
Therefore, the probability of selecting two carnations is (1/3) * (5/17) = 5/51.
So, the probability of selecting two carnations is 5/51.
A big flower vase has 5 begonias, 6 carnations, and 7 tulips. Two flowers are randomly selected without replacement. What is the probability of selecting two carnations? Express in the simplest form of fraction.
1 answer