The total number of flowers in the vase is 5+6+7 = 18.
There are a total of 6 carnations out of 18 flowers, so the probability of selecting the first carnation is 6/18.
After selecting the first carnation, there are 5 carnations left out of 17 flowers, so the probability of selecting the second carnation is 5/17.
Therefore, the probability of selecting two carnations is (6/18) * (5/17) = 30/306 = 5/51.
So, the probability of selecting two carnations is 5/51.
A big flower vase has 5 begonias, 6 carnations, and 7 tulips. Two flowers are randomly selected without replacement What is the probability of selecting two camations? Express the answer in the simplest form of fraction.
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