A big flower vase has 5 begonias 6 carnations and 7 tulips. Two flowers are randomly selected without replacement. What is the probablity of selecting two carnations? Express your answer in simplest form of a fraction

Answer 1

First, we need to find the total number of ways to choose 2 flowers out of the 18 total flowers:

${18\choose 2} = \frac{18!}{2!(18-2)!} = \frac{18 \times 17}{2 \times 1} = 153$

Next, we need to find the number of ways to choose 2 carnations out of the 6 total carnations:

${6\choose 2} = \frac{6!}{2!(6-2)!} = \frac{6 \times 5}{2 \times 1} = 15$

Finally, we can calculate the probability of selecting two carnations by dividing the number of ways to choose 2 carnations by the total number of ways to choose 2 flowers:

Probability = $\frac{15}{153} = \frac{5}{51}$

Therefore, the probability of selecting two carnations is $\boxed{\frac{5}{51}}$.

Answer 2

?

Answer 3

The probability of selecting two carnations is 5/51.