The total number of flowers in the vase is 5 + 6 + 7 = 18.
The probability of selecting the first carnation is 6/18 = 1/3.
After selecting the first carnation, the total number of flowers remaining is 18 - 1 = 17.
The probability of selecting the second carnation is 5/17.
Therefore, the probability of selecting two carnations is:
(1/3) * (5/17) = 5/51
So, the probability of selecting two carnations is 5/51.
A big flower vase has 5 begonias, 6 carmations, and 7 tulips. Two flowers are randomly selected without replacement. What is the probability of selecting two camations? Express the answer in the simplest form of fraction
1 answer