A bicyclist was riding down a road. At 2.0 s, his speed was 2.0 m/s. At 5.0 s, his speed was 8.0 m/s. What was his acceleration from 2 to 5 s?

Answer 1

a = ∆v/∆t = (8-2)m/s / (5-2)s = 6m/s /3s = 2 m/s^2