linear programming
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A bicycle manufacturer builds racing bikes and mountain bikes. Materials for the racing bike cost $110 while labor to build them is $120. Materials for the mountain bike cost $140 and labor is $180. The company budgeted $31,800 for labor and $26,150 for materials. How many of each bicycle did they build?
3 answers
nr = number of racing bikes
nm = number of mountain bikes
lc = labor cost
lc = 120 nr + 180 nm
lc </= $31,800
mc = materials cost
mc = 110 nr + 140 nm
mc /= $26,150
sorry, do not need programming, nothing to maximize oer minimize, simple solution of two equations, two unknowns
120 nr + 180 nm = $31,800
110 nr + 140 nm = $26,150
solve for nr and nm
nm = number of mountain bikes
lc = labor cost
lc = 120 nr + 180 nm
lc </= $31,800
mc = materials cost
mc = 110 nr + 140 nm
mc /= $26,150
sorry, do not need programming, nothing to maximize oer minimize, simple solution of two equations, two unknowns
120 nr + 180 nm = $31,800
110 nr + 140 nm = $26,150
solve for nr and nm
Ya but how would you solve for it using Substitution or Elimination?