A bicycle has wheels with a diameter of 0.570 m. It accelerates uniformly and the rate of rotation of its wheels increases from 181 rpm to 260 rpm in a time of 19.9 s. Find the linear acceleration of the bicycle.
i tried converting everything to linear to use a linear equation but i cant get the right answer
1 answer
wi=181rpm=2pi(181/60)=18.95rad/s wf=260rpm=2pi(260/60)=27.23rad/s angular acceleration=a/r=wf-wi/t a/0.285=27.23-18.95/19.9 3.51a=0.416 a=0.12m/s^2
2 answers