A bear spies some honey and takes off from rest, accelerating at a rate of 2.3 m/s2.v If the honey is 18 m away, how fast will his snout be going when it reaches the treat?

Answer 1

We can use the following equation to solve the problem:

v^2 = u^2 + 2*a*s

where v is the final velocity, u is the initial velocity (which is 0), a is the acceleration, and s is the distance traveled.

v^2 = 0^2 + 2 * 2.3 * 18

v^2 = 0 + 2 * 2.3 * 18

v^2 = 82.8

To find the final velocity, we need to take the square root:

v = sqrt(82.8)

v = 9.1 m/s

So the bear's snout will be going 9.1 m/s when it reaches the honey.