A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 25.0° and the angle of refraction is 14.0°, find the critical angle for the liquid when surrounded by air.
im not sure how to start this problem.
2 answers
just kidding i figured it out.
first, find the index of refraction
n= sin25/sin14
then, critical angle= arcsin(1/n)=arcsin(sin14/sin25) about 35 degrees, work it out and check me.
n= sin25/sin14
then, critical angle= arcsin(1/n)=arcsin(sin14/sin25) about 35 degrees, work it out and check me.