A beam having a length of 20 metres is pivoted at its mid point. A 200 newton load is located at a point 5 m from the right hand end of the beam. A 300 newton load is located at a point 8 m from the right hand end. In order for the beam to be in equilibrium, what load is required at the extreme left end of the beam?

1 answer

let the load be x N
10x = 5(200) + 2(300)
10x = 1600
x = 160 N