A beam having a length of 20 metres is pivoted at its mid point. A 200 newton load is located at a point 5 m from the right hand end of the beam. A 300 newton load is located at a point 8 m from the right hand end. In order for the beam to be in equilibrium, what load is required at the extreme left end of the beam?

asked by MOe

10 years ago

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1 answer

let the load be x N
10x = 5(200) + 2(300)
10x = 1600
x = 160 N

answered by Reiny

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Question

A beam having a length of 20 metres is pivoted at its mid point. A 200 newton load is located at a point 5 m from the right hand end of the beam. A 300 newton load is located at a point 8 m from the right hand end. In order for the beam to be in equilibrium, what load is required at the extreme left end of the beam?

1 answer

let the load be x N
10x = 5(200) + 2(300)
10x = 1600
x = 160 N

Ask a New Question or answer this question.

Reiny · Accepted Answer

let the load be x N 10x = 5(200) + 2(300) 10x = 1600 x = 160 N