A bead of mass m = 33.5 kg is released from point A which is located 5 m above the ground and slides on a frictionless track. Determine the bead's speed when it reaches point C which is located 2.0 m above the ground.

Answer 1

falls 3 meters
(1/2) m v^2 = m g (3)

v^2 = 2 mg(3)

v = sqrt (2 m g(3)

You should remember forever
This:
when something falls distance h from zero speed at top and no air drag
v = sqrt (2 g h)
mass does not matter for this