A battery of em.f 12v and internal resistance r =1.5ohms is connected to an external resistance of 30ohm calculate the potential drop across the 30ohm resistance and in the internal resistance

Answer 1

The circuit can be represented as follows:

___________ ____________ ________
| |----| 30 ohm |----| |
| 12V | | resistor | | 1.5ohm|
| battery |----| |----| |
|_________| |___________| |______|

Using Ohm's law, we can calculate the current flowing through the circuit:

I = V / R
where V is the voltage of the battery, and R is the total resistance of the circuit:

R = 30 ohm + 1.5 ohm = 31.5 ohm

I = 12V / 31.5 ohm = 0.38 A

Now we can calculate the potential drop across the 30 ohm resistor:

V = I * R
V = 0.38 A * 30 ohm = 11.4 V

Finally, we can calculate the potential drop across the internal resistance of the battery:

V = I * r
V = 0.38 A * 1.5 ohm = 0.57 V

Therefore, the potential drop across the 30 ohm resistor is 11.4 V, and the potential drop across the internal resistance is 0.57 V.