To calculate the terminal potential difference of the battery, we need to consider the voltage drop across its internal resistance.
The total resistance in the circuit is given by the sum of the resistance of the battery (3 ohms) and the external resistor (20 ohms): 3 ohms + 20 ohms = 23 ohms.
Using Ohm's law, we can calculate the current flowing through the circuit: I = V/R, where V is the terminal potential difference of the battery. Rearranging this equation, we have: V = IR.
Substituting the values we have: V = (15 volts)⋅(23 ohms) = 345 volts.
Therefore, the terminal potential difference of the battery is 345 volts.
The lost volts of the battery can be calculated by subtracting the terminal potential difference from the emf (electromotive force) of the battery.
The emf of the battery is given as 15 volts.
Therefore, the lost volts of the battery = emf - terminal potential difference = 15 volts - 345 volts = -330 volts.
Note: The lost volts of the battery indicates that there is a drop in potential difference due to the internal resistance of the battery.
A battery of 15volts and internal resistance 3ohms is connected to a resistor of resistance 20ohms calculate both terminal potential difference & Lost volts of the battery
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