Asked by fredah
a battery has internal resistace of 4ohm and the emf is 12v .The battery used to maintain a current in a resistor of resistance of 20 ohm
a)Calculate the current in the circuit
b)the potential difference across the ends of the 20 ohm resistor and the energy transformed in the 20 ohm resitor
a)Calculate the current in the circuit
b)the potential difference across the ends of the 20 ohm resistor and the energy transformed in the 20 ohm resitor
Answers
Answered by
bobpursley
current in circuit:
12/(24) = .5 amp
potential on resister
.5a*20ohm=10volts
energy= I^2 R= .25*20=5 watts
12/(24) = .5 amp
potential on resister
.5a*20ohm=10volts
energy= I^2 R= .25*20=5 watts
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