Asked by Luis
A battery has an internal resistance of 0.42. A number of identical light bulbs, each with a resistance of 31.500, are connected in parallel across the battery terminals. The terminal voltage of the battery is observed to be one-half the emf of the battery. How many bulbs are connected?
Answers
Answered by
bobpursley
well, I*.42=31.5/n * I
n= 31.5/.42
n= 31.5/.42
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