A battery (ε= 10.0V, r = 0.50Ω) is connected to three light bulbs in series (R1= 15.0Ω, R2= 21.0Ω, R3= 24.0Ω). Calculate the current delivered by the battery.

Answer 1

I = E/(r+R1+R2+R3) = 10/(0.5+15+21+24) = 0.165A.